The height at which

eSaral Updated on:
Question:

The height at which the acceleration due to gravity becomes $\frac{\mathrm{g}}{9}$ (where $\mathrm{g}=$ the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :-

  1. $\frac{R}{2}$

  2. $\sqrt{2} \mathrm{R}$

  3. $2 \mathrm{R}$

  4. $\frac{R}{\sqrt{2}}$

Correct Option: , 3

Solution:

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