Question:
The height of mercury surfaces in the two arms of the manometer shown in figure (13-E1) are $2 \mathrm{~cm}$ and $8 \mathrm{~cm}$. Atmospheric pressure $=1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$. Find
(a) the pressure of the gas in the cylinder and
(b) the pressure of mercury at the bottom of the $U$ tube.
Solution:
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.