The integral

Question:

The integral $\int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x$ is equal to :

  1. $(x-1) e^{x+\frac{1}{x}}+c$

  2. $x e^{x+\frac{1}{x}}+c$

  3. $(x+1) e^{x+\frac{1}{x}}+c$

  4. $-x e^{x+\frac{1}{x}}+c$


Correct Option:

Solution:

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