The lanthanoid that does NOT show +4 oxidation state is:
Question:
The lanthanoid that does NOT show $+4$ oxidation state is:
Correct Option: , 3
Solution:
Europium(Eu)
Atomic No. $-63$
Electronic configuration - $[\mathrm{Xe}] 4 f^{7} 6 s^{2}$
It shows only $+2$ and $+3$ oxidation state.