The perimeter of a circular field is 242 m. The area of the field is

(c) 4658.5 m2
Let the radius be r m.
We know:

Perimeter of a circle $=2 \pi r$

Thus, we have:

$2 \pi r=242$

$\Rightarrow 2 \times \frac{22}{7} \times r=242$

$\Rightarrow \frac{44}{7} \times r=242$

$\Rightarrow r=\left(242 \times \frac{7}{44}\right)$

$\Rightarrow r=\frac{77}{2}$

$\therefore$ Area of the circle $=\pi r^{2}$

$=\left(\frac{22}{7} \times \frac{77}{2} \times \frac{77}{2}\right) \mathrm{m}^{2}$

$=4658.5 \mathrm{~m}^{2}$