Question:
The perimeter of a rectangular field is $82 \mathrm{~m}$ and its area is $400 \mathrm{~m}^{2}$. Find the breadth of the rectangle.
Solution:
Let the breadth of the rectangle be $=x$ metres . Then
Perimeter $=82$ metres
2 (length+breadth ) $=82$
(length $+x$ ) $=41$
length $=41-x$
And area of the rectangle
length $\times$ breadth $=400$
$(41-x) x=400$
$41 x-x^{2}=400$
$x^{2}-41 x+400=0$
$x^{2}-25 x-16 x+400=0$
$x(x-25)-16(x-25)=0$
$(x-25)(x-16)=0$
$(x-25)=0$
$x=25$
or
$(x-16)=0$
$x=16$
Since perimeter is 82 meter. So breadth can't be 25 meter.
Hence, breadth 16 metres