Question:
The radii of the ends of a bucket of height 24 cm are 15 cm and 5 cm. Find its capacity. (Take π = 22/7)
Solution:
Height of a bucket $=24 \mathrm{~cm}$
$R=15 \mathrm{~cm}$
$r=5 \mathrm{~cm}$
Therefore,
Capacity of the bucket
$=\frac{\pi h}{3}\left[h^{2}+R r+r^{2}\right]$
$=\frac{22}{7} \times \frac{24}{3} \times\left[(15)^{2}+15 \times 5+(5)^{2}\right]$
$=8171.42 \mathrm{~cm}^{3}$