The ratio in which (4, 5) divides the join of (2, 3) and (7, 8) is
The ratio in which (4, 5) divides the join of (2, 3) and (7, 8) is
(a) −2 : 3
(b) −3 : 2
(c) 3 : 2
(d) 2 : 3
The co-ordinates of a point which divided two points $\left(x_{1}, y_{1}\right)$ and $\left(x_{2}, y_{2}\right)$ internally in the ratio $m: n$ is given by the formula,
$(x, y)=\left(\left(\frac{m x_{2}+n x_{1}}{m+n}\right),\left(\frac{m y_{2}+n y_{1}}{m+n}\right)\right)$
Here it is said that the point (4, 5) divides the points A(2,3) and B(7,8). Substituting these values in the above formula we have,
$(4,5)=\left(\left(\frac{m(7)+n(2)}{m+n}\right),\left(\frac{m(8)+n(3)}{m+n}\right)\right)$
Equating the individual components we have,
$4=\frac{m(7)+n(2)}{m+n}$
$4 m+4 n=7 m+2 n$
$3 m=2 n$
$\frac{m}{n}=\frac{2}{3}$
Hence the correct choice is option (d).