# The resistance

Question:

The resistance $\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}$, where $\mathrm{V}=(50 \pm 2) \mathrm{V}$ and $\mathrm{I}=(20 \pm 0.2) \mathrm{A}$. The percentage error in $\mathrm{R}$ is ' $x$ ' \%. Sthe value of ' $x$ ' to the nearest integer is

Solution:

$\frac{\Delta \mathrm{R}}{\mathrm{R}} \times 100=\frac{\Delta \mathrm{V}}{\mathrm{V}} \times 100+\frac{\Delta \mathrm{I}}{\mathrm{I}} \times 100$

$\%$ error in $\mathrm{R}=\frac{2}{50} \times 100+\frac{0.2}{20} \times 100$

$\%$ error in $\mathrm{R}=4+1$

$\%$ error in $\mathrm{R}=5 \%$