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Question:
The resistance $\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}$, where $\mathrm{V}=(50 \pm 2) \mathrm{V}$ and $\mathrm{I}=(20 \pm 0.2) \mathrm{A}$. The percentage error in $\mathrm{R}$ is ' $x$ ' \%. Sthe value of ' $x$ ' to the nearest integer is
Solution:
$\frac{\Delta \mathrm{R}}{\mathrm{R}} \times 100=\frac{\Delta \mathrm{V}}{\mathrm{V}} \times 100+\frac{\Delta \mathrm{I}}{\mathrm{I}} \times 100$
$\%$ error in $\mathrm{R}=\frac{2}{50} \times 100+\frac{0.2}{20} \times 100$
$\%$ error in $\mathrm{R}=4+1$
$\%$ error in $\mathrm{R}=5 \%$
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