Question:
The solution set of the inequation |x + 2| > 5 is
Solution:
for $|x+2|>5$
We get,
$x+2>5$ or $x+2<-5$
i.e. $\quad x>3 \quad($ By adding $-2$ to both sides of $x+2>5)$
and $x<-7 \quad($ By adding $-2$ to both sides of $x+2<-5)$
Hence, solution set of $|x+2|>5$ is
$(-\infty,-7) \cup(3, \infty)$
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