Question:
The standard Gibbs energy for the given cell reaction in $\mathrm{kJ} \mathrm{mol}^{-1}$ at $298 \mathrm{~K}$ is :
$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \rightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$
$\mathrm{E}^{\circ}=2 \mathrm{~V}$ at $298 \mathrm{~K}$
(Faraday's constant, $\mathrm{F}=96000 \mathrm{C} \mathrm{mol}^{-1}$ )
Correct Option: 1
Solution: