Question:
The system containing the rails and the wire of the previous problem is kept vertically in a uniform horizontal magnetic field $\mathrm{B}$ that is perpendicular to the rails. It is found that the wire stays in equilibrium. If the wire ab is replaced by another wire of double its mass, how long will it take in falling through a distance equal to its length?
Solution:
$t=\sqrt{\frac{2 l}{g}}$
Comments
Prince Gupta
Aug. 27, 2024, 6:35 a.m.
Thankyou sir aapka explanation aur mere teacher Saleem Ahmed sir fi ka explanation bhi same hai baaki YouTube aur other websites per explanation totally wrong hai
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