Question:
The value of the integral $\int_{0}^{\pi}|\sin 2 \mathrm{x}| \mathrm{dx}$ is
Solution:
Put $2 \mathrm{x}=\mathrm{t} \Rightarrow 2 \mathrm{dx}=\mathrm{dt}$
$\Rightarrow \mathrm{I}=\frac{1}{2} \int_{0}^{2 \pi}|\sin \mathrm{t}| \mathrm{dt}$
$=\int_{0}^{\pi}|\sin t| d t$
$=2$
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