The zeros of the polynomial $x^{2}-2 x-3$ are
(a) −3, 1(b) −3, −1(c) 3, −1(d) 3, 1
(c) $3,-1$
Let $f(x)=x^{2}-2 x-3=0$
$=x^{2}-3 x+x-3=0$
$=x(x-3)+1(x-3)=0$
$=(x-3)(x+1)=0$
$=x=3$ or $x=-1$
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