Question:
There are 20 tickets numbered as 1, 2, 3,..., 20 respectively. One ticket is drawn at random. What is the probability that the number on the ticket drawn is a multiple of 5?
(a) $\frac{1}{4}$
(b) $\frac{1}{5}$
(C) $\frac{2}{5}$
(d) $\frac{3}{10}$
Solution:
(b) $\frac{1}{5}$
Explanation:
Total number of tickets = 20
Out of the given ticket numbers, multiples of 5 are 5, 10, 15 and 20.
Number of favourable outcomes = 4
$\therefore P($ getting a multiple of 5$)=\frac{4}{20}=\frac{1}{5}$
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