Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:

Question:

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:

If the three coins are tossed simultaneously again, compute the probability of:

3. At least one Head coming up

4. Getting more Tails than Heads

5. Getting more heads than tails

Solution:

1. Probability of 2 Heads coming up $=\frac{\text { Favorable out come }}{\text { Total out come }}$

$=\frac{36}{100}=0.36$

2. Probability of 3 Heads coming up $=\frac{\text { Favorable out come }}{\text { Total out come }}$

$=\frac{12}{100}=0.12$

3. Probability of at least one head coming up $=\frac{\text { Favorable out come }}{\text { Total out come }}$

$=\frac{38+36+12}{100}$

$=\frac{86}{100}=0.86$

4. Probability of getting more Heads than Tails $=\frac{\text { Favorable out come }}{\text { Total out come }}$

$=\frac{36+12}{100}$

$=\frac{48}{100}$

5. Probability of getting more tails than heads $=\frac{\text { Favorable out come }}{\text { Total out come }}$

$=\frac{14+38}{100}$

$=\frac{52}{100}=0.52$