Tick (✓) the correct answer

Question:

Tick (✓) the correct answer

$\left(\frac{31}{-4}+\frac{-5}{8}\right)=?$

(a) $\frac{67}{8}$

(b) $\frac{57}{8}$

(c) $\frac{-57}{8}$

(d) $\frac{-67}{8}$

 

Solution:

(d) $\frac{-67}{8}$

$\frac{31}{-4}=\frac{-31}{4}$

We have:

$\left(\frac{31}{-4}+\frac{-5}{8}\right)=\left(\frac{-31}{4}+\frac{-5}{8}\right)$

LCM of 4 and 8 is 8 , that is, $(4 \times 1 \times 2)$.

$\left(\frac{-31}{4}+\frac{-5}{8}\right)=\frac{2 \times(-31)+1 \times(-5)}{8}$

$=\frac{(-62)+(-5)}{8}$

$=\frac{-67}{8}$

 

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