Question:
Two dice are thrown at the same time. Determine the probability that the difference of the numbers on the two dice is 2.
Solution:
The total number of sample space in two dice, n (S) = 6 x 6 = 36
Let $E=$ Event of getting the numbers whose difference is 2
$=\{(1,3),(2,4),(3,5),(4,6),(3,1),(4,2),(5,3),(6,4)\}$
$\therefore \quad n(E)=8$
$\therefore \quad P(E)=\frac{n(E)}{n(S)}=\frac{8}{36}=\frac{2}{9}$
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