Two monochromatic beams A and B of equal intensity I,

Question:

Two monochromatic beams A and B of equal intensity I, hit a screen. The number of photons hitting the screen by beam A is twice that by beam B. Then what inference can you make about their frequencies?

Solution:

Let nA be the no.of photons falling per second from beam A and nB be the no.of photons falling per second from beam B.

Given,

No.of photons hitting the screen by A is twice that of B

Therefore, nA = 2nB

Energy from the beam A = hvA

Energy from the beam B = hvB

Intensity = I = nAvA = nBvB

vB = 2vA

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