Question:
Two particles having masses $4 \mathrm{~g}$ and $16 \mathrm{~g}$ respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is $\mathrm{n}: 2$. The value of $\mathrm{n}$ will be
Solution:
(1)
$\because$ relation $\mathrm{b} / \mathrm{w}$ kinetic energy $\backslash$ momentum is
$\mathrm{P}=\sqrt{2 \mathrm{mKE}} \quad(\because \mathrm{KE}=$ same $)$
$\frac{\mathrm{p}_{1}}{\mathrm{p}_{2}}=\sqrt{\frac{\mathrm{m}_{1}}{\mathrm{~m}_{2}}}$
$\frac{n}{2}=\sqrt{\frac{4}{16}}$
$n=1$
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