Two unequal angles of a parallelogram are in the ratio 2: 3. Find all its angles in degrees.
Question:

Two unequal angles of a parallelogram are in the ratio 2: 3. Find all its angles in degrees.

Solution:

Let A = 2x and B = 3x

Now, A +B = 180  [Co-interior angles are supplementary]

2x + 3x – 180  [AD II BC and AB is the transversal)

⟹ 5x = 180

x = 180/5

x = 36

Therefore, A = 2 × 36 = 72

b = 3 × 36 = 108

Now, A = C = 72 [Opposite side angles of a parallelogram are equal)

B = D = 108

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