Question:
Use $\mathrm{R}=8.3 \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ wherever required.
The temperature and the dew point in an open room are $20^{\circ} \mathrm{C}$ and $10^{\circ} \mathrm{C}$. If the room temperature drops to $15^{\circ} \mathrm{C}$, what will be the new dew point?
Solution:
Air becomes saturated at $10^{\circ} \mathrm{C}$.
If room temperature falls to $15^{\circ} \mathrm{C}$ then also dew point $=10^{\circ} \mathrm{C}$.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.