Question:
Using screw gauge of pitch $0.1 \mathrm{~cm}$ and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as:
Correct Option: , 4
Solution:
$\mathrm{LC}=\frac{\text { pitch }}{\text { CSD }}=\frac{0.1 \mathrm{~cm}}{50}=0.002 \mathrm{~cm}$
So any measurement will be integral Multiple of LC.
So ans. will be $2.124 \mathrm{~cm}$
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