What is the probability that an ordinary year has 53 Sundays?

Question:

What is the probability that an ordinary year has 53 Sundays?

Solution:

GIVEN: An ordinary year

TO FIND: Probability that a non leap year has 53 Sundays.

Total number of days in an ordinary year is 365days

Hence number of weeks in an ordinary year is 

In an ordinary year we have 52 complete weeks and 1 day which can be any day of the week i.e. SUNDAY, MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY and SATURDAY

To make 53 Sundays the additional day should be Sunday

Hence total number of days is 7

Favorable day I.e. Sunday is 1

We know that PROBABILITY = 

Hence probability that an ordinary year has 53 Sundays is equal to

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