Question:
White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.
Solution:
When white phosphorous reacts with chlorine:
P4 + 6Cl2 4PCl3
PCl3 + 3H2O H3PO3 + 4HCl ]*4
P4 +6Cl2 +12H2O 4H3PO3 +12HCl
Moles of white P= 62/124 = 0.5mol
1mol of white P4 produces HCl = 12mol
0.5 mol of white P4 will produce HCl = 12*0.8 = 6mol
Mass of HCl = 6*36.5 = 219.0g
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