Question:
Write the acute angle $\theta$ satisfying $\sqrt{3} \sin \theta=\cos \theta$.
Solution:
We have: $\sqrt{3} \sin \theta=\cos \theta$
$\Rightarrow \sqrt{3} \sin \theta=\cos \theta$
$\Rightarrow \frac{\sin \theta}{\cos \theta}=\frac{1}{\sqrt{3}}$
$\Rightarrow \tan \theta=\tan 30^{\circ}$
$\Rightarrow \theta=30^{\circ}$
Hence the acute angle is
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