- In CGS units it is defined by the equation:
$\mu \mathrm{B}=(e \cdot h) / 2 m_{\mathrm{e}} \mathrm{c}$
- In SI units it is defined by the equation:
$\mu_{\mathrm{B}}=e \cdot h / 2 m_{e}$
- The electron possesses magnetic moment due to its spin motion also $\overrightarrow{ M }_{ s }=\frac{ e }{ m _{ e }} \overrightarrow{ s }$ .where $\overrightarrow{ s }$ is spin angular momentum of electron and $S=\pm \frac{1}{2}\left(\frac{h}{2 \pi}\right)$
- The total magnetic moment of electron is the vector sum of its magnetic moments due to orbital and spin motion.
- The resultant angular momentum of the atom is given by vector sum of orbital and spin angular momentum due to all electrons. Total angular momentum $\vec{J}=\vec{L}+\vec{S}$
- The resultant magnetic moment $\overrightarrow{ M _{j}}=- g \left(\frac{ e }{2 m }\right) \overrightarrow{ J }$
where g is Lande’s splitting factor which depends on state of an atom.
For pure orbital motion g = 1 and pure spin motion g = 2.
Also Read: Biot Savart’s Law Click here for the Video tutorials of Magnetic Effect of Current Class 12About eSaral At eSaral we are offering a complete platform for IIT-JEE & NEET preparation. The main mission behind eSaral is to provide education to each and every student in India by eliminating the Geographic and Economic factors, as a nation’s progress and development depends on the availability of quality education to each and every one. With the blend of education & technology, eSaral team made the learning personalized & adaptive for everyone.For free video lectures and complete study material, Download eSaral APP.
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