JEE Main Cut off (2025,2024,2023, 2022, 2021 and 2019)
JEE Mains & Advanced
JEE Main exams are important for students who aspired to be an engineer and want to pass out from reputed institutes like IITs, NITs, IIITs, etc., they are the dream institutes for any engineering aspirants. Of Course, many students try their best to succeed in JEE Main and JEE Advance exams and pass with flying colors.
However, after clearing JEE Mains students should be prepared beforehand and set the target, or being specific they should analyze and prepare accordingly for the cutoff range. JEE Main 2025 cut-off marks have been released by the NTA on their website. JEE Main cutoff marks are the minimum cutoff marks students should score to qualify for the JEE Advance exam. Cutoff marks are issued for each category viz., general, OBC, SC, and ST by NTA. Students should always refer to the cutoff marks of the previous year. NTA also issues the category-wise merit lists of students who secured All India Ranks. Students can also estimate their expected All India Rank using a JEE Main percentile to rank calculator before official results are announced
Factors Considered By NTA To Set Up Cutoff Marks
NTA will calculate the percentile for each candidate in a particular session as follows:
- Total Percentile:- Number of students who appeared for a session in JEE Mains and have a raw score equal to or less than the total raw score scored by the topper /total students who have appeared for the exams * 100.
- Mathematics Percentile:- Number of students who appeared for the mathematics exam for a session in JEE Mains and have a raw score equal to or less than the highest raw score scored by the student in mathematics /total students who have appeared for the exams * 100.
- Physics Percentile:- Number of students who appeared for the physics exam for a session in JEE Mains and have a raw score equal to or less than the highest raw score obtained by the student in physics /total students who have appeared for the exams * 100.
- Chemistry Percentile:- Number of students who appeared for the Chemistry exam for a session in JEE Mains and have a raw score equal to or less than the highest raw score obtained by the student in chemistry /total students who have appeared for the exams * 100.
JEE Main cut off 2025
| Category | JEE Main 2025 Cutoff Percentile |
|---|---|
| General (UR) | 93.1023262 |
| EWS (Economically Weaker Section) | 80.3830119 |
| OBC-NCL | 79.4313582 |
| SC | 61.1526933 |
| ST | 47.9026465 |
| General-PwD | 0.0079349 |
JEE Main cut off 2024
|
Category |
Cutoff Marks |
|
General (UR) |
93.2362181 |
|
Economically Weaker Section (EWS) |
81.3266412 |
|
Other Backward Classes (OBC-NCL) |
79.6757881 |
|
Scheduled Caste (SC) |
60.0923182 |
|
Scheduled Tribe (ST) |
46.6975840 |
|
General-Persons with Disabilities (Gen-PwD) |
0.0018700 |
JEE Main cut off 2023
The below table shows the category-wise JEE Main 2023 cutoff of the NTA score based on B.E./B. Tech (Paper 1):-
|
Category |
Minimum Percentile Cut off |
Maximum Percentile Cutoff |
Total |
|
UR- ALL (General) |
90.7788642 |
100 |
98612 |
|
UR-PH (General- PwD) |
0.0013527 |
90.7638032 |
2685 |
|
EWS-ALL |
75.6229025 |
90.7773597 |
25057 |
|
OBC-ALL |
73.6114227 |
90.7773597 |
67613 |
|
SC-ALL |
51.9776027 |
90.7773597 |
37536 |
|
ST-ALL |
37.2348772 |
90.7773597 |
18752 |
JEE Main Cutoff Types
JEE Main cutoff is of two types. Firstly JEE Main qualifying cutoff -which is released by NTA students should secure a qualifying cutoff in JEE Main exam to appear in JEE Main advance exams. Secondly, the JEE Main admission cutoff was released by the Joint Seat Allocation Authority (JoSAA) on behalf of participating colleges. Students who are aspiring the admission to NITs, IIITs, CFITs, and other private colleges need JEE Main 2023 admission cutoff as minimum marks to enter these colleges.
JEE Main Cutoff 2022
Cutoff Of JEE Main 2020 released by NTA below:
|
Category |
Minimum Percentile Cutoff |
Maximum Percentile Cutoff |
|
UR- ALL (General) |
88.4121383 |
100 |
|
UR-PH (General- PwD) |
0.0031029 |
88.3784882 |
|
EWS-ALL |
63.1114141 |
88.3784882 |
|
OBC-ALL |
67.0090297 |
88.3784882 |
|
SC-ALL |
43.0820954 |
88.3784882 |
|
ST-ALL |
26.7771328 |
88.3784882 |
JEE Main CutOff Marks 2021
|
Category |
Minimum Percentile Cutoff |
Maximum Percentile Cutoff |
|
UR- ALL (General) |
87.8992241 |
100 |
|
UR-PH (General- PwD) |
0.0096375 |
87.8273359 |
|
EWS-ALL |
66.2214845 |
87.8950071 |
|
OBC-NCL |
68.0234447 |
87.8950071 |
|
SC-ALL |
46.8825338 |
87.8950071 |
|
ST-ALL |
34.6728999 |
87.8474721 |
JEE Main CutOff Marks 2020 (Category Wise)
|
Category |
Cutoff |
|
UR- ALL (General) |
90.3765335 |
|
UR-PH (General- PwD) |
0.0618524 |
|
EWS-ALL |
70.2435518 |
|
OBC-NCL |
72.8887969 |
|
SC-ALL |
50.1760245 |
|
ST-ALL |
39.0696101 |
Factors That Influence The Percentile Calculation
Students should understand the JEE Main marks vs percentile relationship, as raw marks do not directly translate into ranks
- The raw score of the students:- Individual score of students before the calculation of percentile. It gives an estimate of how much he/she has scored in exams out of 360 marks. These marks are not normalized to 100. As it is done in the case of the highest scorer.
- Quality of the paper: The difficulty of the level exam also influences percentile calculation. For example, the percentile calculation of a student will differ for the same student who attempted the exam in another session.
- Performance of the other students appearing in the exam: To calculate the score of a student in session 1 depends on the performance of other students who have appeared in session 1. Students who have scored the highest will be normalized to 100.
Rules Applied By NTA If One Or More Students Secure The Same Percentile In JEE Main Exams
- Students scoring the highest percentile in mathematics will be given the first preference.
- Then also the tie exists between the students after applying the above rule for the student who has scored highest percentile in physics will be given first preference.
- After applying the above rules also the tie doesn't break, the student who scored highest in chemistry will be given first preference.
- If after applying the above rule tie persists then the older student will be given first preference.
Importance of Normalisation Method
Overview
Normalization procedures help NTA to prepare JEE scores unbiasedly and decide the ranks and merit lists of students. Fourth time this method is assimilated into JEE Main exams. This method helps students to calculate and estimate their scores on the exam. On this basis, they can assess which college they can get admission to.
By comparing scores unanimously from various sessions of JEE Main exam students can estimate the percentile and judge their performance and can take decisions accordingly. At all state level and national levels, this technique has been used widely.
This normalization process helps in preparing unbiased results as JEE Main exams are conducted in two sessions and 2 shifts in each session, moreover, different sessions have different levels of difficulty in each session. To ensure justice and unbiasedness in results follow the rule of equality and justice this procedure has introduced. It is also used in major educational tests conducted nationwide.
Importance of normalization method:-
- Despite maintaining the same level of difficulty in question papers of each session it may vary due to exams in two sessions with two shifts in each session. There may be the likelihood that the difficulty level varies in every session there comes the role of normalization of the procedure.
- Students who appear in a session that has a higher level of difficulty tend to lose marks as compared to students who appear in a session with a lower level of difficulty. There comes the role of normalization procedure by calculating and deciding the score at the same scale.
- By introducing normalization procedures NTA has assured students that every student has equal opportunity to be judged at the same level of scale without any student being benefited or deluded.
How to get Admission to NIT through JEE Main?
Students who have scored equal to or more than JEE Main cutoff and more than 75 % marks in the 12th board, however, there is relaxation for reserved category students they have to score 65% marks in 12th board exams, are preferred for admission in NI
Ts through JEE Main, by participating in counseling procedures scheduled by JoSAA.
Marks Required to Get Admission to Different Institutes
For seeking admission to different institutes after attaining JEE Main qualifying marks, students should rank within the opening and closing rank institutes for joining different courses offered in NITs, IIITs, and other GFITs. Admission depends largely on your rank, which can be estimated in advance using a JEE Main percentile to rank tool based on previous years’ data.
Frequently Asked Questions (FAQs) – JEE Main Cutoff
1. What is the JEE Main cutoff?
JEE Main cutoff is the minimum percentile score that a candidate must obtain to qualify for JEE Advanced and to be eligible for admission into NITs, IIITs, GFTIs, and other participating institutes through counseling.
2. Who releases the JEE Main cutoff?
The National Testing Agency (NTA) releases the qualifying cutoff percentile, while the JoSAA (Joint Seat Allocation Authority) releases the admission cutoffs for various institutes and branches.
3. What is the JEE Main 2025 cutoff for General category?
The JEE Main 2025 cutoff percentile for General (UR) category is 93.1023262, as released by NTA.
4. Is JEE Main cutoff released category-wise?
Yes. JEE Main cutoff is released category-wise, including:
-
General (UR)
-
EWS
-
OBC-NCL
-
SC
-
ST
-
General-PwD
Each category has a different qualifying percentile.
5. What is the difference between qualifying cutoff and admission cutoff?
-
Qualifying cutoff: Minimum percentile required to appear for JEE Advanced
-
Admission cutoff: Rank required to get admission into specific colleges and branches through JoSAA counseling
6. Does qualifying the JEE Main cutoff guarantee admission to NITs or IITs?
No. Qualifying the cutoff does not guarantee admission. Admission depends on:
-
Your All India Rank (AIR)
-
Category
-
Home State quota
-
Opening and closing ranks of institutes and branches
7. Why does JEE Main cutoff change every year?
JEE Main cutoff changes due to:
-
Number of candidates appearing
-
Difficulty level of the paper
-
Performance of students
-
Normalization across multiple sessions
8. Can two students with the same marks have different percentiles?
Yes. Due to normalization, students appearing in different shifts may get different percentiles even with the same marks, depending on the difficulty level of their session.
9. How is JEE Main percentile calculated?
JEE Main percentile is calculated using the formula:
Percentile =
100 × (Number of candidates with score ≤ yours) ÷ (Total candidates in that session)
This is done separately for each session and subject.
10. What is normalization in JEE Main?
Normalization is a process used by NTA to ensure fairness across multiple exam shifts. It adjusts scores so that no student is disadvantaged due to a tougher paper or benefited due to an easier one.
11. Is JEE Main cutoff based on marks or percentile?
JEE Main cutoff is always based on percentile, not raw marks. Raw marks are only used internally to calculate percentiles.
12. What marks are required to qualify JEE Advanced?
There is no fixed marks requirement. Qualification depends on percentile cutoff, which varies each year and differs by category.
13. Is previous year cutoff important for preparation?
Yes. Previous year cutoffs help students:
-
Set realistic score targets
-
Understand competition trends
-
Plan preparation and college preferences
14. What factors influence JEE Main percentile calculation?
Key factors include:
-
Raw score
-
Difficulty level of the shift
-
Performance of other candidates in the same session
-
Subject-wise scores (Physics, Chemistry, Maths)
15. What happens if two students get the same percentile?
NTA applies tie-breaking rules in this order:
-
Higher Mathematics percentile
-
Higher Physics percentile
-
Higher Chemistry percentile
-
Older candidate
16. What is the minimum eligibility for admission to NITs through JEE Main?
Candidates must:
-
Score above JEE Main cutoff
-
Have 75% marks in Class 12 (65% for reserved categories)
-
Participate in JoSAA counseling
17. Does JEE Main cutoff differ for home state quota?
Yes. Home State quota cutoffs are usually lower than All India quota cutoffs and vary from state to state.
18. Can I get admission with a low percentile?
Admission with a low percentile is possible in:
-
State engineering colleges
-
Some private institutes
-
Certain categories through reservation quotas
However, top NITs and IITs require high percentiles and ranks.
19. How many students qualify JEE Advanced through JEE Main?
Only the top 2.5 lakh candidates (category-wise) based on JEE Main percentiles are allowed to appear for JEE Advanced.
20. Why is understanding cutoff important for JEE aspirants?
Understanding cutoff helps students:
-
Avoid unrealistic expectations
-
Choose the right colleges and branches
-
Plan second attempts or alternate career paths strategically