Let

Question: Let $A=\{2,3,4,5\}$ and $B=\{1,3,4\}$. If $R$ is the relation from $A$ to $B$ given by a $R b$ if "a is a divisor of $b$ ". Write $R$ as a set of ordered pairs. Solution: Since $R=\{(a, b): a, b \in N: a$ is a divisor of $b\}$ So, $R=\{(2,4),(3,3),(4,4)\}$...

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Using factor theorem, show that g(x) is a factor of p(x), when

Question: Using factor theorem, show that g(x) is a factor of p(x), when $p(x)=x^{4}-x^{2}-12, g(x)=x+2$ Solution: Let: $p(x)=x^{4}-x^{2}-12$ Here, $x+2=0 \Rightarrow x=-2$ By the factor theorem, (x+ 2) is a factor ofthe given polynomial ifp(-2) = 0.Thus, we have: $p(-2)=\left[(-2)^{4}-(-2)^{2}-12\right]$ $=(16-4-12)$ $=0$ Hence,(x+ 2) is a factor of the given polynomial....

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A = {1, 2, 3, 4, 5, 6, 7, 8}

Question: $A=\{1,2,3,4,5,6,7,8\}$ and if $R=\{(x, y): y$ is one half of $x, x, y \in A\}$ is a relation on $A$, then write $R$ as a set of ordered pairs. Solution: Since $R=\{(x, y): y$ is one half of $x ; x, y \in A\}$ So, $R=\{(2,1),(4,2),(6,3),(8,4)\}$...

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If

Question: If $A=\{3,5,7\}$ and $B=\{2,4,9\}$ and $R$ is a relation given by "is less than", write $R$ as a set ordered pairs. Solution: Since, $R=\{(x, y): x, y \in N$ and $xy\}$ $\mathrm{R}=\{(3,4),(3,9),(5,9),(7,9)\}$...

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Define an equivalence relation.

Question: Define an equivalence relation. Solution: A relationRon setAis said to be an equivalence relation iff(i) it is reflexive,(ii) it is symmetric and(iii) it is transitive.RelationRon setAsatisfying all the above three properties is an equivalence relation....

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Using factor theorem, show that g(x) is a factor of p(x), when

Question: Using factor theorem, show that g(x) is a factor of p(x), when $p(x)=2 x^{4}+9 x^{3}+6 x^{2}-11 x-6, g(x)=x-1$ Solution: Let: $p(x)=2 x^{4}+9 x^{3}+6 x^{2}-11 x-6$ Here, $x-1=0 \Rightarrow x=1$ By the factor theorem, (x-1) is a factor ofthe given polynomial ifp(1) = 0.Thus, we have: $p(1)=\left(2 \times 1^{4}+9 \times 1^{3}+6 \times 1^{2}-11 \times 1-6\right)$ $=(2+9+6-11-6)$ $=0$ Hence, $(x-1)$ is a factor of the given polynomial....

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Define a transitive relation.

Question: Define a transitive relation. Solution: A relationRon a setAis said to be transitive iff $(a, b) \in R$ and $(b, c) \in R$ $\Rightarrow(a, c) \in R$ for all $a, b, c \in R$ i. e. $a R b$ and $b R c$ $\Rightarrow a R c$ for all $a, b, c \in R$...

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The following table gives the number of boys of a particular age in a class of 40 students.

Question: The following table gives the number of boys of a particular age in a class of 40 students. Calculate the mean age of the students Solution: Given: First of all prepare the frequency table in such a way that its first column consist of the values of the variate $\left(x_{i}\right)$ and the second column the corresponding frequencies $\left(f_{i}\right)$. Thereafter multiply the frequency of each row with corresponding values of variable to obtain third column containing $\left(f_{i} x_...

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Define a symmetric relation.

Question: Define a symmetric relation. Solution: A relationRon a setAis said to be symmetric iff $(a, b) \in R$ $\Rightarrow(b, a) \in R$ for all $a, b \in A$ i. e. $a R b \Rightarrow b R a$ for all $a, b \in A$...

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Define a symmetric relation.

Question: Define a symmetric relation. Solution: A relationRon a setAis said to be symmetric iff $(a, b) \in R$ $\Rightarrow(b, a) \in R$ for all $a, b \in A$ i. e. $a R b \Rightarrow b R a$ for all $a, b \in A$...

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Using factor theorem, show that g(x) is a factor of p(x), when

Question: Using factor theorem, show that g(x) is a factor of p(x), when $p(x)=2 x^{3}+7 x^{2}-24 x-45, g(x)=x-3$ Solution: Let: $p(x)=2 x^{3}+7 x^{2}-24 x-45$ Now, $x-3=0 \Rightarrow x=3$ By the factor theorem, (x-3) is a factor of the given polynomialifp(3) = 0.Thus, we have: $p(3)=\left(2 \times 3^{3}-7 \times 3^{2}-24 \times 3-45\right)$ $=(54+63-72-45)$ $=0$ Hence,(x-3) is a factor of the given polynomial....

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Define a reflexive relation.

Question: Define a reflexive relation. Solution: A relationRonAis said to be reflexive iff every element ofAis related to itself. i.e. $R$ is reflexive $\Leftrightarrow(a, a) \in R$ for all $a \in A$...

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Using factor theorem, show that g(x) is a factor of p(x), when

Question: Using factor theorem, show that g(x) is a factor of p(x), when $p(x)=x^{3}-8, g(x)=x-2$ Solution: Let: $p(x)=x^{3}-8$ Now, $g(x)=0 \Rightarrow x-2=0 \Rightarrow x=2$ By the factor theorem, (x 2) is a factor of the given polynomialifp(2) = 0.Thus, we have: $p(2)=\left(2^{3}-8\right)=0$ Hence, $(x-2)$ is a factor of the given polynomial....

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Let

Question: Let $A=\{3,5,7\}, B=\{2,6,10\}$ and $R$ be a relation from $A$ to $B$ defined by $R=\{(x, y): x$ and $y$ are relatively prime $\}$. Then, write $R$ and $R^{-1}$. Solution: R= {(x,y) :xandyare relatively prime}Then, R= {(3, 2), (5, 2), (7, 2), (3, 10), (7, 10), (5, 6), (7, 6)} So, $R^{-1}=\{(2,3),(2,5),(2,7),(10,3),(10,7),(6,5),(6,7)\}$...

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If p(x)=2x3−11x2−4x+5 and g

Question: If $p(x)=2 x^{5}-11 x^{2}-4 x+5$ and $g(x)=2 x+1$, show that $g(x)$ is not a factor of $p(x)$. Solution: $p(x)=2 x^{3}-11 x^{2}-4 x+5$ $g(x)=2 x+1=2\left(x+\frac{1}{2}\right)=2\left[x-\left(-\frac{1}{2}\right)\right]$ Putting $x=-\frac{1}{2}$ in $p(x)$, we get $p\left(-\frac{1}{2}\right)=2 \times\left(-\frac{1}{2}\right)^{3}-11 \times\left(-\frac{1}{2}\right)^{2}-4 \times\left(-\frac{1}{2}\right)+5=-\frac{1}{4}-\frac{11}{4}+2+5=-\frac{12}{4}+7=-3+7=4 \neq 0$ Therefore, by factor theore...

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If

Question: If $A=\{2,3,4\}, B=\{1,3,7\}$ and $R=\{(x, y): x \in A, y \in B$ and $xy\}$ is a relation from $A$ to $B$, then write $R^{-1}$. Solution: Since $R=\{(x, y): x \in A, y \in A$ and $xy\}$, R= {(2, 3), (2, 7), (3, 7), (4, 7)}So, $R^{-1}=\{(3,2),(7,2),(7,3),(7,4)\}$...

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If p(x)=x3−5x2+4x−3 and g

Question: If $p(x)=x^{3}-5 x^{2}+4 x-3$ and $g(x)=x-2$, show that $p(x)$ is not a multiple of $g(x)$. Solution: $p(x)=x^{3}-5 x^{2}+4 x-3$ $g(x)=x-2$ Puttingx= 2 inp(x), we get $p(2)=2^{3}-5 \times 2^{2}+4 \times 2-3=8-20+8-3=-7 \neq 0$ Therefore, by factor theorem, (x 2) is not a factor ofp(x).Hence,p(x) is not a multiple ofg(x)....

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Let

Question: Let $R=\left\{(x, y):\left|x^{2}-y^{2}\right|1\right)$ be a relation on set $A=\{1,2,3,4,5\}$. Write $R$ as a set of ordered pairs. Solution: Ris the set of ordered pairs satisfying the above relation. Also, no two different elements can satisfy the relation; only the same elements can satisfy the given relation. So, R = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5)}...

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Find the value of p, if the mean of the following distribution is 20.

Question: Find the value ofp, if the mean of the following distribution is 20. Solution: Given: Mean $=20$ First of all prepare the frequency table in such a way that its first column consist of the values of the variate $\left(x_{i}\right)$ and the second column the corresponding frequencies $\left(f_{i}\right)$. Thereafter multiply the frequency of each row with corresponding values of variable to obtain third column containing $\left(f_{i} x_{i}\right)$. Then, sum of all entries in the column...

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If R is a symmetric relation on a set A, then write a relation between

Question: If $R$ is a symmetric relation on a set $A$, then write a relation between $R$ and $R^{-1}$ Solution: Here,Ris symmetric on the setA. Let $(a, b) \in R$ $\Rightarrow(b, a) \in R$ [Since $R$ is symmetric] $\Rightarrow(a, b) \in R^{-1}$ [Bydefinitionofinverserelation $\Rightarrow R \subset R^{-1}$ Let $(x, y) \in R^{-1}$ $\Rightarrow(y, x) \in R$ [By definition of inverse relation] $\Rightarrow(x, y) \in R$ [Since $R$ is symmetric] $\Rightarrow R^{-1} \subset R$ Thus, $R=R^{-1}$...

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The polynomial p(x)

Question: The polynomial $p(x)=x^{4}-2 x^{3}+3 x^{2}-a x+b$ when divided by $(x-1)$ and $(x+1)$ leaves the remainders 5 and 19 respectively. Find the values of $a$ and $b$. Hence, find the remainder when $p(x)$ is divided by $(x-2)$. Solution: Let $p(x)=x^{4}-2 x^{3}+3 x^{2}-a x+b$ Now, When $p(x)$ is divided by $(x-1)$, the remainder is $p(1)$. When $p(x)$ is divided by $(x+1)$, the remainder is $p(-1)$ Thus, we have: $p(1)=\left(1^{4}-2 \times 1^{3}+3 \times 1^{2}-a \times 1+b\right)$ $=(1-2+3...

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Find the missing frequency (p) for the following distribution whose mean is 7.68.

Question: Find the missing frequency (p) for the following distribution whose mean is 7.68. Solution: Given: Mean $=7.68$ First of all prepare the frequency table in such a way that its first column consist of the values of the variate $\left(x_{i}\right)$ and the second column the corresponding frequencies $\left(f_{i}\right)$. Thereafter multiply the frequency of each row with corresponding values of variable to obtain third column containing $\left(f_{i} x_{i}\right)$. Then, sum of all entrie...

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Find the missing value of p for the following distribution whose mean is 12.58

Question: Find the missing value ofpfor the following distribution whose mean is 12.58 Solution: Given: Mean $=12.58$ First of all prepare the frequency table in such a way that its first column consist of the values of the variate $\left(x_{i}\right)$ and the second column the corresponding frequencies $\left(f_{i}\right)$. Thereafter multiply the frequency of each row with corresponding values of variable to obtain third column containing $\left(f_{i} x_{i}\right)$. Then, sum of all entries in...

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If

Question: If $R=\{(x, y): x+2 y=8\}$ is a relation on $N$ by, then write the range of $R$. Solution: $R=\{(x, y): x+2 y=8, x, y \in N\}$ Then, the values ofycan be 1, 2, 3 only. Also,y= 4 cannot result inx= 0 becausexis a natural number.Therefore, range ofRis {1, 2, 3}....

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Write the smallest reflexive relation on set

Question: Write the smallest reflexive relation on setA= {1, 2, 3, 4}. Solution: Here,A= {1, 2, 3, 4}Also, a relation is reflexive iff every element of the set is related to itself. So, the smallest reflexive relation on the setAisR= {(1, 1), (2, 2), (3, 3), (4, 4)}...

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