Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g
Question:

Calculate the number of $\mathrm{kJ}$ of heat necessary to raise the temperature of $60.0 \mathrm{~g}$ of aluminium from $35^{\circ} \mathrm{C}$ to $55^{\circ} \mathrm{C}$. $\mathrm{Molar}$ heat capacity of $\mathrm{Al}$ is $24 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$.

 

Solution:

From the expression of heat (q),

$q=m . c \cdot \Delta T$

Where,

c = molar heat capacity

m = mass of substance

$\Delta T=$ change in temperature

Substituting the values in the expression of q:

$q=\left(\frac{60}{27} \mathrm{~mol}\right)\left(24 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)(20 \mathrm{~K})$

q = 1066.7 J

q = 1.07 kJ

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