A cloassroom is 11 m long, 8 m wide and 5 m high.

Question:

A cloassroom is 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls (including doors, windows, etc.)

Solution:

Lenght of the classroom $=11 \mathrm{~m}$

Width $=8 \mathrm{~m}$

Height $=5 \mathrm{~m}$

We have to find the sum of the areas of its floor and the four walls (i.e., like an open box).

$\therefore$ The sum of areas of the floor and the four walls $=($ length $\times$ width $)+2 \times($ width $\times$ height $+$ length $\times$ height $)$

$=(11 \times 8)+2 \times(8 \times 5+11 \times 5)$

$=88+2 \times(40+55)$

$=88+190$

$=278 \mathrm{~m}^{2}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now