Question:
A die is thrown once. The probability of getting an even number is
(a) $\frac{1}{2}$
(b) $\frac{1}{3}$
(C) $\frac{1}{6}$
(d) $\frac{5}{6}$
Solution:
Total number of outcomes = 6.
Out of the given numbers, even numbers are 2, 4 and 6.
Numbers of favourable outcomes = 3.
$\therefore P$ (getting an even number) $=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$
$=\frac{3}{6}=\frac{1}{2}$
Thus, the probability of getting an even number is $\frac{1}{2}$.
Hence, the correct answer is option (a).
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