Question:
AB is a diameter and AC is a chord of a circle with centre 0 such that ∠BAC = 30°. The tangent at C intersects extended AB at a point D. Prove that BC
= BD.
Solution:
A circle is drawn with centre O and AB is a diameter.
AC is a chord such that ∠BAC = 30°.
Given AB is a diameter and AC is a chord of circle with certre O, ∠BAC = 30°.
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