Question:
Evaluate:
$\sqrt[3]{-216}$
Solution:
$\sqrt[3]{-216}$
By prime factorisation:.png)
$216=2 \times 2 \times 2 \times 3 \times 3 \times 3$
$=(2 \times 2 \times 2) \times(3 \times 3 \times 3)$
$\sqrt[3]{-216}=-(2 \times 3)=-6$
$\therefore \sqrt[3]{-216}=-(\sqrt[3]{216})=-6$
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