Question:
Evaluate: $\left\{\left(\frac{-2}{3}\right)^{3}\right\}^{-2}$
Solution:
$\left\{\left(\frac{-2}{3}\right)^{3}\right\}^{-2}=\left(\frac{-2}{3}\right)^{-6}=\left(\frac{3}{-2}\right)^{6}=\frac{3^{6}}{-2^{6}}=\frac{729}{64}$
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