Question:
Factorise:
x2 − ax − bx + ab
Solution:
By suitably arranging the terms:
$x^{2}-a x-b x+a b=x^{2}-b x-a x+a b$
$=\left(x^{2}-b x\right)-(a x-a b)$
$=x(x-b)-a(x-b)$
$=(x-b)(x-a)$
$\therefore x^{2}-a x-b x+a b=(x-b)(x-a)$
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