Factorise:

Question:

Factorise:
p2 + 6p − 16

Solution:

The given expression is $p^{2}+6 p-16$.

Find two numbers that follow the conditions given below:

Sum $=6$

Product $=-16$

Clearly, the numbers are 8 and $-2$.

$p^{2}+6 p-16=p^{2}+8 p-2 p-16$

$=p(p+8)-2(p+8)$

$=(p+8)(p-2)$

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