Question:
Factorise:
4n2 − 8n + 3
Solution:
The given expression is $4 n^{2}-8 n+3$.
Find two numbers that follow the conditions given below:
Sum $=-8$
Product $=4 \times 3=12$
Clearly, the numbers are $-6$ and $-2$.
$4 n^{2}-8 n+3=4 n^{2}-2 n-6 n+3$
$=2 n(2 n-1)-3(2 n-1)$
$=(2 n-1)(2 n-3)$
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