Factorise:

Question:

Factorise:
9 + 6z + z2

Solution:

We have:

$9+6 z+z^{2}=z^{2}+6 z+9$

$=z^{2}+2 \times x \times 3+(3)^{2}$

$=(z+3)^{2}$

$\therefore 9+6 z+z^{2}=(z+3)^{2}$

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