Factorise:

Question:

Factorise:
1 − 6x + 9x2

Solution:

We have:

$1-6 x+9 x^{2}=9 x^{2}-6 x+1$

$=(3 x)^{2}-2 \times 3 x \times 1+(1)^{2}$

$=(3 x-1)^{2}$

$\therefore 1-6 x+9 x^{2}=(3 x-1)^{2}$

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