Question:
Factorise:
(2x + 5y)2 − 1
Solution:
We have:
$(2 x+5 y)^{2}-1=(2 x+5 y)^{2}-(1)^{2}$
$=\{(2 x+5 y)+1\}\{(2 x+5 y)-1\}$
$=(2 x+5 y+1)(2 x+5 y-1)$
$\therefore(2 x+5 y)^{2}-1=(2 x+5 y+1)(2 x+5 y-1)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.