Question:
Factorise:
16a2 − 225b2
Solution:
We have:
$16 a^{2}-225 b^{2}=(4 a)^{2}-(15 b)^{2}$
$=(4 a+15 b)(4 a-15 b)$
$\therefore 16 a^{2}-225 b^{2}=(4 a+15 b)(4 a-15 b)$
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