Question:
Factorise:
x3 − 3x2 + x − 3
Solution:
We have:
$x^{3}-3 x^{2}+x-3=\left(x^{3}-3 x^{2}\right)+(x-3)$
$=x^{2}(x-3)+1(x-3)$
$=(x-3)\left(x^{2}+1\right)$
$\therefore x^{3}-3 x^{2}+x-3=(x-3)\left(x^{2}+1\right)$
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