Factorise:

Question:

Factorise:
(x − 2y)2 + 4x − 8y

Solution:

We have:

$(x-2 y)^{2}+4 x-8 y=(x-2 y)^{2}+4(x-2 y)$

$=(x-2 y)(x-2 y)+4(x-2 y)$

$=(x-2 y)\{(x-2 y)+4\}$

$=(x-2 y)(x-2 y+4)$

$\therefore(x-2 y)^{2}+4 x-8 y=(x-2 y)(x-2 y+4)$

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