Question:
Factorise:
6x2 − 17x − 3
Solution:
The given expression is $6 x^{2}-17 x-3$.
Find two numbers that follow the conditions given below :
Sum $=-17$
Product $=6 \times-3=-18$
Clearly, the numbers are $-18$ and 1 .
$6 x^{2}-17 x-3=6 x^{2}-18 x+x-3$
$=6 x(x-3)+1(x-3)$
$=(6 x+1)(x-3)$
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