Question:
Find the additive inverse of:
(i) $\frac{7}{-10}$
(ii) $\frac{8}{5}$.
Solution:
(i) $\frac{7}{-10}=\frac{7 \times-1}{-10 \times-1}=\frac{-7}{10}$
Additive inverse of $\frac{-7}{10}$ is $\frac{7}{10}$.
(ii) Additive inverse of $\frac{8}{5}$ is $\frac{-8}{5}$.
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