Find the area of trapezium with base 15 cm and height 8 cm,

Given:

Lengths of the parallel sides are $15 \mathrm{~cm}$ and $9 \mathrm{~cm}$.

Height $=8 \mathrm{~cm}$

Area of trapezium $=\frac{1}{2} \times($ Sum of the opposite sides $) \times($ Distance between the parallel sides $)$

$=\frac{1}{2} \times(15+9) \times(8)$

$=96 \mathrm{~cm}^{2}$