Find the area of trapezium with base 15 cm and height 8 cm,

Question:

Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.

Solution:

Given:

Lengths of the parallel sides are $15 \mathrm{~cm}$ and $9 \mathrm{~cm}$.

Height $=8 \mathrm{~cm}$

Area of trapezium $=\frac{1}{2} \times($ Sum of the opposite sides $) \times($ Distance between the parallel sides $)$

$=\frac{1}{2} \times(15+9) \times(8)$

$=96 \mathrm{~cm}^{2}$

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