Question:
If $A$ and $B$ are matrices of the same order, then $(3 A-2 B)^{\top}$ is equal to________
Solution:
$(3 A-2 B)^{\top}$
$=(3 A)^{\top}-(2 B)^{\top}$ [For any two matrices $X$ and $Y,(X+Y)^{\top}=X^{\top}+Y^{\top}$ ]
$=3 A^{\top}-2 B^{\top}$ $\left[(k X)^{\top}=k X^{\top}\right.$, where $k$ is any constant $]$
If $A$ and $B$ are matrices of the same order, then $(3 A-2 B)^{\top}$ is equal to $3 A^{T}-2 B^{T}$
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