Mark (✓) against the correct answer

Question:

Mark (✓) against the correct answer

$\left(\frac{-6}{5}\right)^{-1}=?$

(a) $\frac{6}{5}$

(b) $\frac{-6}{5}$

(c) $\frac{5}{6}$

(d) $\frac{-5}{6}$

 

Solution:

(d) $\frac{-5}{6}$

$\left(\frac{-6}{5}\right)^{-1}=\left(\frac{5}{-6}\right)^{1}=\frac{5}{-6}=\frac{5 \times-1}{-6 \times-1}=\frac{-5}{6}$

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