Question:
Mark (✓) against the correct answer
$\left(\frac{-6}{5}\right)^{-1}=?$
(a) $\frac{6}{5}$
(b) $\frac{-6}{5}$
(c) $\frac{5}{6}$
(d) $\frac{-5}{6}$
Solution:
(d) $\frac{-5}{6}$
$\left(\frac{-6}{5}\right)^{-1}=\left(\frac{5}{-6}\right)^{1}=\frac{5}{-6}=\frac{5 \times-1}{-6 \times-1}=\frac{-5}{6}$
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