Mark (✓) against the correct answer

Question:

Mark (✓) against the correct answer

$\left(\frac{-1}{3}\right)^{3}=?$

(a) $\frac{-1}{9}$

(b) $\frac{1}{9}$

(c) $\frac{-1}{27}$

(d) $\frac{1}{27}$

Solution:

(c) $\frac{-1}{27}$

$\left(\frac{-1}{3}\right)^{3}=\frac{-1^{3}}{3^{3}}=\frac{-1}{27}$

 

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